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fiber optic
So I was presented a problem here by one of the professors here at the school which I found rather interesting. I'd never considered this problem before as I don't think it arises to often.

j^j =

That's j raised to the power of j.

If you're not familiar with the concept of j then move along. If there's enough incorrect answers or a lot of time passes (a day or so) without any responses I'll post a hint.

Edit: You can use a calculator if you like but I'd like to see how you derived it. So just poking that into the machine and posting a number isn't going to get you very far.
DakianDelomast
Are you using j to represent an imaginary number?
fiber optic
QUOTE(DakianDelomast @ Oct 29 2004, 05:34 PM)
Are you using j to represent an imaginary number?

Move along.
DakianDelomast
Bah its just a simple question. I've seen it written with both j and i so STFU
AgaBoogaBoo
Is that the full problem?
AgaBoogaBoo
What are we supposed to do?
fiber optic
QUOTE(DakianDelomast @ Oct 29 2004, 05:35 PM)
Bah its just a simple question. I've seen it written with both j and i so STFU

Yes j = i. EE's use j because i is current. Sheesh calm down.
DakianDelomast
I'm calm. You damn EEs. tongue.gif
DakianDelomast
sqrt(-1)^sqrt(-1) Hmmmm interesting.
fiber optic
QUOTE(DakianDelomast @ Oct 29 2004, 05:40 PM)
sqrt(-1)^sqrt(-1) Hmmmm interesting.

Progress thumbs_up.gif
DakianDelomast
So far the only one I like is -sin(1) + i*cos(1)
dukenukem
that problem looks very very familiar to me .... ij ll try and solve it after a short nap.


this is from google : i^i = 0.207879576
fiber optic
QUOTE(dukenukem @ Oct 29 2004, 06:52 PM)
this is from google : i^i = 0.207879576

That's it but how did it arrive at that?
Cyclone
2 + 2 = 5! Fuck this shit



My math grade speaks for itself.
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